Optimal. Leaf size=374 \[ \frac {(2 c d-b e) \left (28 c^2 d^2+13 b^2 e^2-4 c e (7 b d+6 a e)\right ) (b+2 c x) \sqrt [4]{a+b x+c x^2}}{168 c^4}+\frac {2 e (d+e x)^2 \left (a+b x+c x^2\right )^{5/4}}{9 c}+\frac {e \left (616 c^2 d^2+117 b^2 e^2-2 c e (243 b d+56 a e)+130 c e (2 c d-b e) x\right ) \left (a+b x+c x^2\right )^{5/4}}{630 c^3}-\frac {\left (b^2-4 a c\right )^{5/4} (2 c d-b e) \left (28 c^2 d^2+13 b^2 e^2-4 c e (7 b d+6 a e)\right ) \sqrt {\frac {(b+2 c x)^2}{\left (b^2-4 a c\right ) \left (1+\frac {2 \sqrt {c} \sqrt {a+b x+c x^2}}{\sqrt {b^2-4 a c}}\right )^2}} \left (1+\frac {2 \sqrt {c} \sqrt {a+b x+c x^2}}{\sqrt {b^2-4 a c}}\right ) F\left (2 \tan ^{-1}\left (\frac {\sqrt {2} \sqrt [4]{c} \sqrt [4]{a+b x+c x^2}}{\sqrt [4]{b^2-4 a c}}\right )|\frac {1}{2}\right )}{336 \sqrt {2} c^{17/4} (b+2 c x)} \]
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Rubi [A]
time = 0.35, antiderivative size = 374, normalized size of antiderivative = 1.00, number of steps
used = 5, number of rules used = 5, integrand size = 22, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.227, Rules used = {756, 793, 626,
637, 226} \begin {gather*} -\frac {\left (b^2-4 a c\right )^{5/4} \sqrt {\frac {(b+2 c x)^2}{\left (b^2-4 a c\right ) \left (\frac {2 \sqrt {c} \sqrt {a+b x+c x^2}}{\sqrt {b^2-4 a c}}+1\right )^2}} \left (\frac {2 \sqrt {c} \sqrt {a+b x+c x^2}}{\sqrt {b^2-4 a c}}+1\right ) (2 c d-b e) \left (-4 c e (6 a e+7 b d)+13 b^2 e^2+28 c^2 d^2\right ) F\left (2 \text {ArcTan}\left (\frac {\sqrt {2} \sqrt [4]{c} \sqrt [4]{c x^2+b x+a}}{\sqrt [4]{b^2-4 a c}}\right )|\frac {1}{2}\right )}{336 \sqrt {2} c^{17/4} (b+2 c x)}+\frac {(b+2 c x) \sqrt [4]{a+b x+c x^2} (2 c d-b e) \left (-4 c e (6 a e+7 b d)+13 b^2 e^2+28 c^2 d^2\right )}{168 c^4}+\frac {e \left (a+b x+c x^2\right )^{5/4} \left (-2 c e (56 a e+243 b d)+117 b^2 e^2+130 c e x (2 c d-b e)+616 c^2 d^2\right )}{630 c^3}+\frac {2 e (d+e x)^2 \left (a+b x+c x^2\right )^{5/4}}{9 c} \end {gather*}
Antiderivative was successfully verified.
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Rule 226
Rule 626
Rule 637
Rule 756
Rule 793
Rubi steps
\begin {align*} \int (d+e x)^3 \sqrt [4]{a+b x+c x^2} \, dx &=\frac {2 e (d+e x)^2 \left (a+b x+c x^2\right )^{5/4}}{9 c}+\frac {2 \int (d+e x) \left (\frac {1}{4} \left (18 c d^2-5 b d e-8 a e^2\right )+\frac {13}{4} e (2 c d-b e) x\right ) \sqrt [4]{a+b x+c x^2} \, dx}{9 c}\\ &=\frac {2 e (d+e x)^2 \left (a+b x+c x^2\right )^{5/4}}{9 c}+\frac {e \left (616 c^2 d^2+117 b^2 e^2-2 c e (243 b d+56 a e)+130 c e (2 c d-b e) x\right ) \left (a+b x+c x^2\right )^{5/4}}{630 c^3}+\frac {\left ((2 c d-b e) \left (28 c^2 d^2+13 b^2 e^2-4 c e (7 b d+6 a e)\right )\right ) \int \sqrt [4]{a+b x+c x^2} \, dx}{56 c^3}\\ &=\frac {(2 c d-b e) \left (28 c^2 d^2+13 b^2 e^2-4 c e (7 b d+6 a e)\right ) (b+2 c x) \sqrt [4]{a+b x+c x^2}}{168 c^4}+\frac {2 e (d+e x)^2 \left (a+b x+c x^2\right )^{5/4}}{9 c}+\frac {e \left (616 c^2 d^2+117 b^2 e^2-2 c e (243 b d+56 a e)+130 c e (2 c d-b e) x\right ) \left (a+b x+c x^2\right )^{5/4}}{630 c^3}-\frac {\left (\left (b^2-4 a c\right ) (2 c d-b e) \left (28 c^2 d^2+13 b^2 e^2-4 c e (7 b d+6 a e)\right )\right ) \int \frac {1}{\left (a+b x+c x^2\right )^{3/4}} \, dx}{672 c^4}\\ &=\frac {(2 c d-b e) \left (28 c^2 d^2+13 b^2 e^2-4 c e (7 b d+6 a e)\right ) (b+2 c x) \sqrt [4]{a+b x+c x^2}}{168 c^4}+\frac {2 e (d+e x)^2 \left (a+b x+c x^2\right )^{5/4}}{9 c}+\frac {e \left (616 c^2 d^2+117 b^2 e^2-2 c e (243 b d+56 a e)+130 c e (2 c d-b e) x\right ) \left (a+b x+c x^2\right )^{5/4}}{630 c^3}-\frac {\left (\left (b^2-4 a c\right ) (2 c d-b e) \left (28 c^2 d^2+13 b^2 e^2-4 c e (7 b d+6 a e)\right ) \sqrt {(b+2 c x)^2}\right ) \text {Subst}\left (\int \frac {1}{\sqrt {b^2-4 a c+4 c x^4}} \, dx,x,\sqrt [4]{a+b x+c x^2}\right )}{168 c^4 (b+2 c x)}\\ &=\frac {(2 c d-b e) \left (28 c^2 d^2+13 b^2 e^2-4 c e (7 b d+6 a e)\right ) (b+2 c x) \sqrt [4]{a+b x+c x^2}}{168 c^4}+\frac {2 e (d+e x)^2 \left (a+b x+c x^2\right )^{5/4}}{9 c}+\frac {e \left (616 c^2 d^2+117 b^2 e^2-2 c e (243 b d+56 a e)+130 c e (2 c d-b e) x\right ) \left (a+b x+c x^2\right )^{5/4}}{630 c^3}-\frac {\left (b^2-4 a c\right )^{5/4} (2 c d-b e) \left (28 c^2 d^2+13 b^2 e^2-4 c e (7 b d+6 a e)\right ) \sqrt {\frac {(b+2 c x)^2}{\left (b^2-4 a c\right ) \left (1+\frac {2 \sqrt {c} \sqrt {a+b x+c x^2}}{\sqrt {b^2-4 a c}}\right )^2}} \left (1+\frac {2 \sqrt {c} \sqrt {a+b x+c x^2}}{\sqrt {b^2-4 a c}}\right ) F\left (2 \tan ^{-1}\left (\frac {\sqrt {2} \sqrt [4]{c} \sqrt [4]{a+b x+c x^2}}{\sqrt [4]{b^2-4 a c}}\right )|\frac {1}{2}\right )}{336 \sqrt {2} c^{17/4} (b+2 c x)}\\ \end {align*}
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Mathematica [A]
time = 10.64, size = 235, normalized size = 0.63 \begin {gather*} \frac {1120 c^4 e (d+e x)^2 (a+x (b+c x))^2+8 c^2 e (a+x (b+c x))^2 \left (117 b^2 e^2+4 c^2 d (154 d+65 e x)-2 c e (243 b d+56 a e+65 b e x)\right )+15 (2 c d-b e) \left (28 c^2 d^2+13 b^2 e^2-4 c e (7 b d+6 a e)\right ) \left (2 c (b+2 c x) (a+x (b+c x))-\sqrt {2} \left (b^2-4 a c\right )^{3/2} \left (\frac {c (a+x (b+c x))}{-b^2+4 a c}\right )^{3/4} F\left (\left .\frac {1}{2} \sin ^{-1}\left (\frac {b+2 c x}{\sqrt {b^2-4 a c}}\right )\right |2\right )\right )}{5040 c^5 (a+x (b+c x))^{3/4}} \end {gather*}
Antiderivative was successfully verified.
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Maple [F]
time = 0.01, size = 0, normalized size = 0.00 \[\int \left (e x +d \right )^{3} \left (c \,x^{2}+b x +a \right )^{\frac {1}{4}}\, dx\]
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \left (d + e x\right )^{3} \sqrt [4]{a + b x + c x^{2}}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int {\left (d+e\,x\right )}^3\,{\left (c\,x^2+b\,x+a\right )}^{1/4} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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